Sounds like the oxygen window myth. Why would the partial pressure of O2 affect the Partial pressure of inert gas? Solubilities of one gas are not effected by solubilities of others. Either you are saturated at a particular partial pressure of inert gas (and hence tissue tension) or you are not - the only way an increase in oxygen would affect this is if the partial pressure of inserts drops - ie gas switch.
Would that be your buddy, Mark?
Right. AFAIK. Considering a single compartment and nitrox to keep it simple.
In your tissue, you have dissolved N2. One way to measure that is concentration. Another is to go with henry's law and use the partial pressure it would be in equilibrium with. Now if the partial pressure of a particular gas in a tissue is higher than the partial pressure of that same gas in the lungs, it's above equilibrium and the molecules will diffuse out of the tissue and, via the blood, into the lungs (offgasing)(it's actually not what's happening, molecules go both ways, but the overall effect is as described). The total partial pressure, tension, of inerts is what's used by buhlmann and GF to determine the ceiling. Oxygen and ambient pressure is irrelevant to that. pInerts(tissue) = pN2(tissue)
In your lungs, on the other hand, the total pressure is the same as ambient, so we have p(ambient) = pO2(lungs)+pN2(lungs)+pH2O. Usually it's assumed that the lungs and loop are saturated with water vapor, which has partial pressure pH2O. Sometimes there's CO2 as well, but not in Buhlmann. pO2 will be the setpoint, pN2 will be the rest.
What GF=0 means is the stop is at p(ambient) = pInerts(tissue)
No a/b, no supersaturation, no nothing.
Therefore pO2(lungs)+pN2(lungs)+pH2O = pN2(tissue)
pO2 and pH2O are greater than 0, so pN2(lungs) < pN2(tissue)
The equilibrium would be with a higher pN2 in the lungs, or a lower one in the tissue, so N2 will migrate to the lungs. So you're offgasing.
With several compartments it gets more complicated, p(ambient) will be the same as the pInerts(tissue) of the compartment that has the highest. So there may be offgasing there and ongasing in others, but the diver will still be ascending.
With trimix and (stupid) switches it's possible to get into situations where He is ongased (faster) while N2 is offgased, so actually the diver needs to go down at first, to equilibrate with the new gas, but then he will ascend.
So the point stands, at GF 0, you will, eventually, reach the surface. A bit academic, tho
AFAIK.
Cheers,
Matthieu