Hi everyone,
Hoping someone can help me out with the basic math for a hypothetical (really!) question.
1. CCR diving with air dil at 50m.
2. I leave the setpoint at 0.7
3. I dive to 50m (6ATM)
4. Arriving at 50m (assume I just did a dil flush)
* My PP02 would be (0.21 x 6 = 1.26ATM)
* My PPN2 would be (0.79 x 6 = 4.74ATM)
Can someone advise if I am correct on the following statements:
5. Because my setpoint is at 0.7, no new O2 is going to get injected (ie I would just breathe down the O2 in the loop)
6. Given the nitrogen is not being metabolised as fast, the relative PPN2 would increase as it becomes a larger and larger percentage of the loop volume
7. I would therefore be way more narked on air dil at 50m with a 0.7 setpoint than I would be breathing air on OC at 50m
8. Using the example above, how could I calculate the equivalent narcosis depth of the O2 depleted air I was breathing.
I'm sure there is a simple formula for this.
Thanks
Hoping someone can help me out with the basic math for a hypothetical (really!) question.
1. CCR diving with air dil at 50m.
2. I leave the setpoint at 0.7
3. I dive to 50m (6ATM)
4. Arriving at 50m (assume I just did a dil flush)
* My PP02 would be (0.21 x 6 = 1.26ATM)
* My PPN2 would be (0.79 x 6 = 4.74ATM)
Can someone advise if I am correct on the following statements:
5. Because my setpoint is at 0.7, no new O2 is going to get injected (ie I would just breathe down the O2 in the loop)
6. Given the nitrogen is not being metabolised as fast, the relative PPN2 would increase as it becomes a larger and larger percentage of the loop volume
7. I would therefore be way more narked on air dil at 50m with a 0.7 setpoint than I would be breathing air on OC at 50m
8. Using the example above, how could I calculate the equivalent narcosis depth of the O2 depleted air I was breathing.
I'm sure there is a simple formula for this.
Thanks